How do you find a level surface representing another surface?

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Homework Help Overview

The problem involves finding a level surface that represents the graph of the function f(x,y) = sqrt(25-x^2). The original poster is tasked with determining a function g(x,y,z) = c that corresponds to this surface.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster expresses uncertainty about how to find g(x,y,z) and questions whether setting sqrt(25-x^2) equal to a constant C is appropriate. Other participants suggest different interpretations of the problem and question the clarity of the notation used for C.

Discussion Status

The discussion is ongoing, with participants exploring various interpretations of the problem. Some guidance has been offered regarding the formulation of g(x,y,z), but there is no explicit consensus on the best approach yet.

Contextual Notes

Some participants mention missing lectures and express difficulty in understanding the question due to its phrasing. There is also a note about the need for clarification on the meaning of C in the context of the problem.

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Homework Statement


The surface S is the graph of f(x,y) = sqrt(25-x^2)

a)Find a level surface g(x,y,z) = c Representing S.
b) with C=?



Homework Equations





The Attempt at a Solution


I have no idea what to do with this question. How should I find g(x,y,z)? Do I let sqrt(25-x^2) = C? I tried this method and the answer is wrong. Am I on the right track?And what does it mean by C=?
 
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http://math.arizona.edu/~calc/Text/Section12.5.pdf
... but surely you've covered this?

Don't know what it means by C=?
Does not look like a general notation.
 
Last edited by a moderator:
Simon Bridge said:
http://math.arizona.edu/~calc/Text/Section12.5.pdf
... but surely you've covered this?

Don't know what it means by C=?
Does not look like a general notation.
I missed 2 weeks of lectures because I was sick, so I am having a really difficult time to catch up...
So basically I take sqrt(25-x^2)-z and solve it for Z?
 
Last edited by a moderator:
Ah - then you should read through that link I gave you.
It is very hard to give you hints without doing the thing for you it's that basic - the link covers the concepts and has examples.

Basically, you put g(x,y,z) = z-f(x,y) = c which gives you a family of 3D surfaces... now, if c=0, you get a simplification that will tell you the basic shape of the surface in 3D.
 
First, [itex]f(x,y)= \sqrt{25- x^2}[/itex] is not a surface in a xyz-coordinate system because you need a coordinate representing z. Rather [itex]z= \sqrt{25- x^2}[/itex] is a surface. And that is the same as [itex]\sqrt{25- x^2}- z= 0[/itex].
 
Its badly phrased isn't it?
I got my interpretation by googling for similar phrasing ... JIC.
shalanheyyo really needs to check with someone else on the course.

It could be the intent is that one put [itex]z=f(x,y)[/itex] then rearrange that so all the "constant" terms are on the RHS and all the terms with x or y or z in them are on the LHS. This would have form g(x,y,z)=c, and it would make sense to ask what c is.
 
I emailed my Prof and the question is actually really simple. I guess I got confused by how the question is worded
 
So are you going to enlighten us?
 

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