MHB How Do You Find the Curvature at (2, 4, -1)?

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To find the curvature at the point (2, 4, -1) for the parametric equations x = 2t, y = 4t^(3/2), and z = -t^2, one must first determine the parameter t that corresponds to this point. After identifying t, the curvature can be calculated using the formula involving the first and second derivatives of the position vector. The discussion encourages sharing work to facilitate assistance and suggests reviewing similar examples from Paul’s Online Notes for guidance. Understanding the method of calculating curvature is essential for solving the problem effectively. Engaging with provided resources can enhance comprehension of the curvature concept in calculus.
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Find the curvature at the point (2, 4, −1).


x = 2t, y = 4t3/2, z = −t2
 
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Please post your work so far, and that will help us help you!
 
carl123 said:
Find the curvature at the point (2, 4, −1).


x = 2t, y = 4t3/2, z = −t2

Hi carl123,

What have you tried? Here's some similar examples from Pauls Online Notes. If you read through them surely you'll know the method of finding the curvature.

Pauls Online Notes : Calculus III - Curvature
 

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