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How do you find the direction and magnitude from a nucleus?

  1. Feb 8, 2009 #1
    1. The problem statement, all variables and given/known data

    The nucleus of an atom has a charge of 65 protons.

    (a) What are the direction and magnitude of the electric field at 4.9 x 10^-10 m from the nucleus?

    (b) What are the direction and magnitude of the force exerted on an electron located at this distance?


    2. Relevant equations
    E= KQ/d^2
    K= 9 x 10^9


    3. The attempt at a solution

    (a) (9 x 10^9)(65)/(4.9 x 10^-10)^2
    = 2.44e30 N

    Please help clarify if (a) is correct, and what exactly is (b) asking, if any different from (a)?
     
  2. jcsd
  3. Feb 8, 2009 #2

    LowlyPion

    User Avatar
    Homework Helper

    I think you need to understand what the charge of 65 protons is.
    http://en.wikipedia.org/wiki/Proton

    It is not 65 coulombs that are the units of the equation you used.

    Having found the field, then b) is asking you to find the force.
     
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