How Do You Find the Field Inside a Polarized Cylinder?

  • Thread starter Thread starter shaun_chou
  • Start date Start date
  • Tags Tags
    Cylindrical Field
Click For Summary
SUMMARY

The discussion centers on solving the electric field inside a uniformly polarized cylinder, as presented in Griffiths problem 4.13. The key equations mentioned are the bound charge density, \(\rho_b = P \cdot \hat{n}\), and the surface bound charge, \(\sigma_b = -\nabla \cdot P\). However, the consensus is that these equations are not necessary for this problem. Instead, applying Gauss's Law is the correct approach to determine the electric field both inside and outside the cylinder.

PREREQUISITES
  • Understanding of Gauss's Law in electrostatics
  • Familiarity with polarization and bound charges
  • Knowledge of Griffiths' "Introduction to Electrodynamics" textbook
  • Basic calculus for evaluating integrals related to electric fields
NEXT STEPS
  • Study Gauss's Law applications in cylindrical symmetry
  • Review the concept of bound charges in polarized materials
  • Examine examples of electric fields in uniformly polarized objects
  • Explore Griffiths problems related to electrostatics for further practice
USEFUL FOR

Students studying electromagnetism, particularly those tackling problems in Griffiths' "Introduction to Electrodynamics," and anyone interested in understanding electric fields in polarized materials.

shaun_chou
Messages
11
Reaction score
0

Homework Statement


This problem is at Griffiths 4.13. A very long cylinder of radius a with a uniform polarization perpendicular to the axis. The question is to solve for the field inside the cylinder.


Homework Equations


\rho_b=P\cdot\hat{n} and \sigma_b=-\nabla\cdot P


The Attempt at a Solution


I can't find a good solution using above equations. Can anyone help me? Thanks a lot!
 
Physics news on Phys.org
I don't think you need those two equations for this problem. You should be looking at Gauss's Law inside and outside the cylinder.
 
Also, \rho_b and \sigma_b are the bound charges (volume and surface respectively) and are not the electric field.

Is your professor suggesting you solve the problem using them, or did you assume you should since the question by Griffiths is right after the section on the bound charges?
 

Similar threads

Replies
4
Views
5K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 7 ·
Replies
7
Views
6K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K