How Do You Inverse Laplace Transform an RLC Circuit Equation?

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SUMMARY

The discussion focuses on deriving the current equation for an RLC circuit with parameters R=12 ohms, L=1.2 henries, and C=30 microfarads under an impulse voltage input. The user successfully applied Kirchhoff's law and Laplace transforms, resulting in the equation I = s/(1.2s^2 + 12s) + 1. To find the inverse Laplace transform, the user recognizes the need to manipulate the equation into a standard form, specifically identifying 1/(1.2s + 12) as suitable for transformation using standard tables.

PREREQUISITES
  • Understanding of RLC circuit theory
  • Familiarity with Laplace transforms
  • Knowledge of inverse Laplace transform techniques
  • Basic application of Kirchhoff's laws
NEXT STEPS
  • Study the properties of the Laplace transform in electrical engineering contexts
  • Learn how to apply the inverse Laplace transform using standard tables
  • Explore the Dirac delta function and its applications in circuit analysis
  • Review examples of RLC circuit response to impulse inputs
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing RLC circuits and their transient responses.

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Homework Statement



Derive an equation to represent the current flowing in an RLC circuit where R=12 L=1.2 C=30microfrards with an impulse voltage input. Assume zero conditions when the switch is closed.

Homework Equations





The Attempt at a Solution


I have used the voltage to equal 1, laplace transformed the RLC values and started from basic Kirschoffs law to give
I= s/(1.2s^2+12s)+1

To complete this I know I need to inverse laplace it but cannot get this equation into a format to do it. Can anyone please help before I pull my hair out how to do this??
 
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1/(1.2s + 12) = (1/1.2) / (s+12/1.2) is of the form a / (s+b) which can be found on any standard table of inverse laplace transforms.

The inverse laplace transform of 1 is the dirac delta function.
 

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