How do you know when a set of observables form a CSCO?

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SUMMARY

The discussion focuses on the criteria for determining when a set of observables forms a Complete Set of Commuting Observables (CSCO), specifically in the context of the hydrogen atom and harmonic oscillator. Key operators such as Hamiltonian (H), angular momentum squared (L^2), and the z-component of angular momentum (L_z) are identified as forming a CSCO for the hydrogen atom. The conversation emphasizes the importance of commutation relations and the need for completeness in the mathematical language of quantum mechanics, particularly when dealing with degenerate eigenvalues and the necessity of additional measurements to resolve states.

PREREQUISITES
  • Understanding of quantum mechanics principles, particularly observables and eigenvalues.
  • Familiarity with the concept of commutation relations in quantum operators.
  • Knowledge of the hydrogen atom and harmonic oscillator models in quantum physics.
  • Basic mathematical proficiency in linear algebra and operator theory.
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  • Study the mathematical framework of Complete Sets of Commuting Observables (CSCO).
  • Learn about the implications of degenerate eigenvalues in quantum mechanics.
  • Explore the role of commutation relations in determining the completeness of observables.
  • Investigate the application of CSCO in solving quantum mechanical problems involving the hydrogen atom and harmonic oscillator.
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Students of quantum mechanics, physicists working with quantum systems, and anyone seeking to deepen their understanding of observables and their role in quantum measurements.

estiface
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I understand that the operators have to commute, and therefore that the measurement of one has no bearing on the measurement of the other. I know that H, L^2, and L_z form a CSCO for the H atom. Basically, I conceptually understand CSCO. Often though, in my class, we will be working on a problem, finding eigenvalues, and then my teacher says "therefore these form a CSCO."

How do you know a set is complete? it seems to me that to make claims of completeness one must try to apply every operator you can think of before excluding any from the set...
My problem is recognizing the completeness in the math language. At which point after finding eigenvalues do you see that these form a CSCO? what are the specific mathematical "pictures" that should trigger "oh, these form a CSCO"? if asked "do these form a CSCO?", how do i check that? (other than checking commutation relations.)

basically, i think my question can be summed up in: what is the mathematical language of CSCO's, especially in context of the H atom or harmonic oscillator?
 
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estiface said:
I understand that the operators have to commute, and therefore that the measurement of one has no bearing on the measurement of the other. I know that H, L^2, and L_z form a CSCO for the H atom. Basically, I conceptually understand CSCO. Often though, in my class, we will be working on a problem, finding eigenvalues, and then my teacher says "therefore these form a CSCO."

How do you know a set is complete? it seems to me that to make claims of completeness one must try to apply every operator you can think of before excluding any from the set...
My problem is recognizing the completeness in the math language. At which point after finding eigenvalues do you see that these form a CSCO? what are the specific mathematical "pictures" that should trigger "oh, these form a CSCO"? if asked "do these form a CSCO?", how do i check that? (other than checking commutation relations.)

basically, i think my question can be summed up in: what is the mathematical language of CSCO's, especially in context of the H atom or harmonic oscillator?

This concept is introduced to distinguish eigenstates of the same eigenvalue from each other, i.e., degenerate states. For operator A, if it has degenerate eigenvalues, say a, all the eigenvector for 'a' form a subspace of dimension > 1, so it's not possible to say for sure what state the particle was in once you make an observation of value a, all you know is after the first observation, the particle's state is in this subspace. In order to pin down the exact state, we have to make another observation which corresponds to a commuting operator, say B. Since A and B commute, the observation of B doesn't disturb the fact that the particle is in the above subspace, but hopefully the eigenspace for the two eigenvalues <a, b> will have fewer degeneracy, which means after the 2nd observation, we have fewer choice for the state of the particle. This keeps going until the degenerate space has dimension 1, then you have a complete set of observables
 
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