- #1

- 93

- 1

f(-1) = 3

f(1) = 3

i tried plugging and chugging

for the first condition:

3 = a - b + c

3 = a + b + c

now i tried subtracting the system to get

0 = 2b

so its solved that b = 0

so now we got a step further towards the goal, and we know we can right the function as

f(x) = ax^2 + c

so now we try plugging and chugging again, but then we get

3 = a + c

3 = a + c

since they are the same equation, i dont know how we can solve for a and c.