How Do You Relate Fitted Curve to Mean, Standard Deviation, and Standard Error?

Click For Summary
SUMMARY

The discussion focuses on relating fitted curves to statistical measures such as mean, standard deviation (SD), and standard error (SE) using MATLAB's Curve Fitting Tool (cftool). The user generated a dataset with 100 points, calculated the mean and standard deviation, and derived the standard error formula. The key conclusion is that understanding how to interpret these statistical measures in the context of fitted curves is essential for accurate data analysis and comparison with the normal distribution's 95% confidence interval.

PREREQUISITES
  • Basic understanding of statistical concepts: mean, standard deviation, and standard error.
  • Familiarity with MATLAB and its Curve Fitting Tool (cftool).
  • Knowledge of normal distribution and its properties.
  • Experience with data generation and manipulation in MATLAB.
NEXT STEPS
  • Explore MATLAB's Curve Fitting Tool (cftool) for advanced fitting techniques.
  • Learn about the implications of standard error in statistical analysis.
  • Study the properties of the normal distribution and its integral for confidence intervals.
  • Investigate methods for visualizing fitted curves against raw data in MATLAB.
USEFUL FOR

Statisticians, data analysts, and students in quantitative fields who are working with statistical data analysis and curve fitting in MATLAB.

coffeem
Messages
91
Reaction score
0

Homework Statement



Given:

clear
n = 100;
x = 1:n;
err = randn(1,n);
mean(err);
std(err);
y = x + err;
cftool

Q - Relate your fitted to the data in y to the mean, S and SE values. You should also compare the fit results to the 95% point on the curve of the integral of the normal distribution.


2. The attempt at a solution

I did the following:

Mean = mean(y)

Standard_Deviation = std(y)

Standard_Error = ((Standard_Deviation).^2)./sqrt(100)


But in all honestly don't know what I have to do. I mean how do I relate the data? I think the problem here is that I do not understand the question. Thanks
 
Physics news on Phys.org
hey does anyone have any ideas for this? i am still stuck... thanks
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 17 ·
Replies
17
Views
4K
Replies
2
Views
1K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 42 ·
2
Replies
42
Views
6K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 10 ·
Replies
10
Views
1K
Replies
28
Views
4K
  • · Replies 6 ·
Replies
6
Views
6K