How Do You Simplify a Cubic Polynomial?

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To simplify the cubic polynomial -x^3 - 3x^2 - 4x - 2, it is essential to factorize it rather than simplify in the traditional sense. The incorrect assumption that x-1 is a factor is clarified, as substituting x=1 does not yield zero. Instead, x+1 is identified as a factor since substituting x=-1 results in zero. Dividing the polynomial by x+1 will reveal the other factor. Accurate factorization is crucial for correctly simplifying cubic polynomials.
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Homework Statement



simplify -x^3 - 3x^2 - 4x - 2
It is equal to -(x-1)(x^2 + 2x + 2)

Not sure how to get that answer, nor how to start it.
 
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Patdon10 said:

Homework Statement



simplify -x^3 - 3x^2 - 4x - 2
It is equal to -(x-1)(x^2 + 2x + 2)

Not sure how to get that answer, nor how to start it.

The word you're looking for is to factorize it, not simplify it. You can't simplify it in the sense that you can simply \frac{\sin(x)}{\cos(x)} to become \tan(x) for example.

Ok so first of all, in order to factorize that cubic you'll need to know one of its roots. Do you know how to check if a polynomial has rational roots?
 
Patdon10 said:

Homework Statement



simplify -x^3 - 3x^2 - 4x - 2
It is equal to -(x-1)(x^2 + 2x + 2)

Not sure how to get that answer, nor how to start it.
Good! Because you shouldn't get that "answer". It is wrong.

Setting x= 1 in that polynomial gives -(1)- 3(1)- 4(1)- 2= -(1+3+ 4+ 2)= -10, not 0. Since x= 1 does NOT make that polynomial 0, x- 1 is NOT a factor. -x^3- 3x^2- 4x- 2 is NOT equal to -(x- 1)(x^2+ 2x+ 2).

However, setting x= -1 gives -(-1)- 3(1)- 4(-1)- 2= 1- 3+ 4- 2= 0 so x-(-1)= x+ 1 is a factor. Divide -x^3- 3x^2- 4x- 2 by x+1 to get the other factor.
 
HallsofIvy said:
Good! Because you shouldn't get that "answer". It is wrong.

Setting x= 1 in that polynomial gives -(1)- 3(1)- 4(1)- 2= -(1+3+ 4+ 2)= -10, not 0. Since x= 1 does NOT make that polynomial 0, x- 1 is NOT a factor. -x^3- 3x^2- 4x- 2 is NOT equal to -(x- 1)(x^2+ 2x+ 2).

However, setting x= -1 gives -(-1)- 3(1)- 4(-1)- 2= 1- 3+ 4- 2= 0 so x-(-1)= x+ 1 is a factor. Divide -x^3- 3x^2- 4x- 2 by x+1 to get the other factor.

Ah yes I shouldn't noticed that at quick glance since -x^3 - 3x^2 - 4x - 2 = -(x^3+3x^2+4x+2) which should have all same sign coefficients in its factors
 
Patdon10 said:

Homework Statement



simplify -x^3 - 3x^2 - 4x - 2
It is equal to -(x-1)(x^2 + 2x + 2)

Not sure how to get that answer, nor how to start it.
-(x-1)(x^2 + 2x + 2)

is equivalent to:

-x^3 -x^2 + 2
 

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