How Do You Solve 0.51 = 1,800((v^2)/13)?

Thread starter randomss444
Start date Jun 4, 2010

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SUMMARY

The equation 0.51 = 1,800((v^2)/13) can be solved by isolating v. First, rearrange the equation to v^2 = (0.51 * 13) / 1800. This simplifies to v^2 = 0.00458333. Taking the square root of both sides yields v = 0.0677. This process demonstrates the application of algebraic manipulation to solve for a variable in a quadratic equation.

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Understanding of algebraic manipulation
Familiarity with solving quadratic equations
Knowledge of basic arithmetic operations
Ability to work with square roots

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Practice solving more complex quadratic equations
Learn about the quadratic formula and its applications
Explore the concept of variable isolation in algebra
Study the principles of dimensional analysis in physics equations

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Jun 4, 2010

randomss444

Homework Statement

Not sure if this is the right section but

How would you go about solving this equation?

0.51 = 1,800((v^2)/13)

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Jun 4, 2010

rl.bhat

Homework Helper

randomss444 said:

Homework Statement

Not sure if this is the right section but

How would you go about solving this equation?

0.51 = 1,800((v^2)/13)

v² = 0.51*13/1800

Now solve for v.