How Do You Solve a Pre Calculus Problem with Congruent Sides and Diagonals?

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Homework Help Overview

The discussion revolves around a pre-calculus problem involving a quadrilateral with two pairs of congruent sides and a diagonal of length 6. The objective is to determine the value of x such that the area of a shaded region is 40% of the area of the unshaded region.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between the areas of the shaded and unshaded regions, setting up equations based on the given proportions. There is an exploration of how to simplify the equations and solve for x.

Discussion Status

Some participants have provided guidance on the setup of the problem and the simplification of equations. There is a general agreement on the approach taken, though no explicit consensus on the correctness of the final value of x has been reached.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information available and the methods discussed.

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[SOLVED] Pre Calculus Homework Problem...Help!

1. Homework Statement

A quadrilateral has two pairs of congruent sides and a longer diagonal of length of 6, as shown. For what value of x will the area of the shaded region be 40% of the area of the unshaded region?


2. Homework Equations

x=.40(6-x)

3. The Attempt at a Solution

x=1.71
 

Attachments

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the area of shaded region is S1 = x*a and of unshaded S2 = (6-x)a. You also know that S1/S2 = 0.4 . Now just solve the equation for x.
 
Pre Cal Hwk Problem: Answer

x(a)/(6-x)(a)= 0.4
The a's cancel out...so that leaves me with: x/(6-x)=0.4 x=2.4/1.4 x=1.71

Is my work correct?
 
It looks fine. The important thing is to realize where the areas came from.
 
Thanks for the help!
 

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