MHB How Do You Solve Advanced Calculus Review Questions?

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To solve advanced calculus review questions, one must determine the horizontal asymptotes of the function g(x) = |f(x)|/(x-2) under the condition that f(x) satisfies f(x+1) ≤ x ≤ f(x) + 1 for all real x. Additionally, for a differentiable function f at zero with f(0) = 0, it is necessary to show that the limit as x approaches zero of the sum of f evaluated at fractions of x equals the product of the harmonic series and f'(x). Participants in the discussion are encouraged to share their approaches and solutions to these problems. Engaging with these types of calculus questions enhances understanding of limits and asymptotic behavior. Mastery of these concepts is crucial for success in advanced calculus.
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1. Find the horizontal asymptotes of the graph of the function $$g(x) = \frac{|f(x)|}{x-2}$$ if $$f(x)$$ satisfies inequality $$f(x+1) \le x \le f(x)+1$$ for every real $$x$$.

2. Let $$f: R->R$$ be a function that is differentiable at zero and such that $$f(0) = 0$$. Show that for each $$n\in\mathbb{N}$$ we have that

$$\lim_{{x}\to{0}} \frac{1}{x} ( f(x) + f(\frac{x}{2}) + ... + f(\frac{x}{n}) ) = (1 + \frac{1}{2} + ... + \frac{1}{n} ) f'(x)$$
 
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What have you tried so far?
 
There are probably loads of proofs of this online, but I do not want to cheat. Here is my attempt: Convexity says that $$f(\lambda a + (1-\lambda)b) \leq \lambda f(a) + (1-\lambda) f(b)$$ $$f(b + \lambda(a-b)) \leq f(b) + \lambda (f(a) - f(b))$$ We know from the intermediate value theorem that there exists a ##c \in (b,a)## such that $$\frac{f(a) - f(b)}{a-b} = f'(c).$$ Hence $$f(b + \lambda(a-b)) \leq f(b) + \lambda (a - b) f'(c))$$ $$\frac{f(b + \lambda(a-b)) - f(b)}{\lambda(a-b)}...

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