The discussion centers on solving the exponential inequality 2^x + 2^(4-x) > 17. The user successfully factored the expression to 2^(-x) * (16 + 2^(2x)) > 17 and later substituted u = 2^x, transforming the inequality into (u^2 - 17u + 16)/u > 0. The final solution was achieved by solving the quadratic inequality, leading to the correct values for x.
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Let u = 2x .scientifico said:Homework Statement
2^x + 2^(4-x) > 17
2.The attempt at a solution
I factorized for 2^(-x) so I have 2^(-x) * (16 + 2^(2x)) > 17 but I don't know what to do after... could you help me ?
thanks
What did you get when you solved for x ?scientifico said:Thanks I figured it out and solved correctly.
(u^2 - 17u +16)/u > 0