How Do You Solve for x in This Algebra Equation?

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Homework Help Overview

The original poster presents an algebraic equation involving variables a and b, seeking assistance in solving for x. The equation is structured as 3bx - ab + 2a^2 = 2ax + 3b^2, and the poster expresses uncertainty about their progress and the correctness of their approach.

Discussion Character

  • Exploratory, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants suggest various methods for isolating x, including factoring and rewriting terms. Some emphasize the importance of ensuring that certain expressions are not zero before dividing. Others express understanding of the original poster's confusion regarding the solution process.

Discussion Status

Multiple participants have contributed different perspectives on how to approach the problem, with some offering step-by-step guidance. The discussion reflects a collaborative effort to clarify the algebraic manipulation needed to isolate x, though no consensus on a single method has been reached.

Contextual Notes

The original poster indicates a time constraint due to an upcoming exam, which adds urgency to their request for help. There is also mention of a textbook answer that lacks explanation, contributing to the poster's confusion.

haengbon
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I'm not sure it is the correct thread, but it did say Algebra homeworks could be posted here too right? :biggrin:

Homework Statement



3bx - ab + 2a^2 = 2ax + 3b^2

solve for the x.

Homework Equations



none

The Attempt at a Solution



3bx - ab + 2a^2 = 2ax + 3b^2
2a^2 - 3b^2 = 2ax - 3bx + ab
2a^2 - 3b^2 = x(2a - 3b) + ab
2a^2 - 3b^2 -ab = x(2a - 3b)

after which, I'm, stuck :confused:I don't know what to do anymore, nor do I know if I'm dog it right! my book says, the answer should be x=a+b. sadly, it doesn't give an explanation as to how it got the answer :cry:please help? I really need to pass my exam two days from now, and solution sets is a big part of it.
 
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You could try writing the left hand side as (2a - 3b) ( ... ) and divide out (2a - 3b) (provided it is not zero).
 
First, put the terms with x on one side and the rest on the other side.Then, factor x out and divide both sides to have the x alone on one side.Finally,simplify.
 
I can understand your struggle when you have the answer but you don't know how they get there, anyway I have much simpler way to do it .. you reached to a good step .. so all what left is to perform a division.. I made a figure illustrating the idea .. just go with me step by step :


http://img189.imageshack.us/img189/9431/11291260.jpg

as you can see it is just a long division but this time it is with two variables .. so how to do it?

well,

first : take a as your variable and anything else as constant (check the red colored writing) divide 2a with 2a^2 put the result up (which is a ) then multiply it with 2a - 3b and write it below 2a^2 - 3b^2-ab (each result below the one that looks similar to it)

second : take b as your variable and anything else as constant (check the blue colored writing) divide -3b with -3b^2 and put the result up (which is b) then multiply it with 2a - 3b and write the result below 2a^2 - 3b^2 -ab ( also put each result below the one that looks similar to it)

thired : change the sign of all the previous results (check the green colored writing) and add every thing , you will end up with zero with tells you that when you divide 2a^2 - 3b^2 -ab with 2a-3b that will give you a+b with no reminder ..

I hope now you got it :) .. and good luck with your test ..
 
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You can rewrite the left side as

2a^2-2b^2 -b^2-ab= 2(a^2-b^2)-b(b+a)=
=2(a-b)(a+b)-b(a+b)= (a+b)(2a-2b-b)=(a+b)(2a-3b)

So the equation becomes: (a+b)(2a-3b)=x(2a-3b)

Divide both sides by 2a-3b (supposing it is not 0) the result is x=a+b.
If 2a-3b=0 any x is solution.

ehild
 
So, the four of us have now provided you with the complete answer :)
 
ohmy :) thank you thank you thank you! I'm glad all of you have responded :redface:
 

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