- #1

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## Homework Statement

## Homework Equations

## The Attempt at a Solution

4x^2-2xy=2-3y^2

x(4x-2y)=2-3y^2 then I'm stuck[/B]

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- Thread starter JKCB
- Start date

- #1

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4x^2-2xy=2-3y^2

x(4x-2y)=2-3y^2 then I'm stuck[/B]

- #2

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if you want to find ##x=f(y)## then view it as a quadratic ##ax^2+bx+c=0## with ##a=4,b=-2y, c=3y^2##.

- #3

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What do I do with the 2 at the end of the original equation?

- #4

SammyS

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Please include a complete statement of your problem## Homework Statement

## Homework Equations

## The Attempt at a Solution

4x^2-2xy=2-3y^2

x(4x-2y)=2-3y^2 then I'm stuck[/B]

Last edited:

- #5

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What do I do with the 2 at the end of the original equation?

Ah yes sorry, I thought it was =0, just incorporate 2 inside c, so ##c=4x^2-2## (or ##c=3y^2-2##)

- #6

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Ah! Well that's going to be fun! Thank you so much!

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