How Do You Solve Linear Systems with Irrational Numbers Precisely?

Click For Summary
SUMMARY

The discussion focuses on solving linear systems containing irrational numbers, specifically the system represented by the equations [2, 1 : 4] and [2√3, √3 : 4√3]. Participants emphasize the importance of expressing solutions precisely without approximating irrational numbers. They highlight that calculators typically provide rational approximations, which may not accurately represent the solutions. The conversation also touches on the concept of linear dependence, indicating that the given system has infinitely many solutions due to the equations being equivalent when manipulated.

PREREQUISITES
  • Understanding of linear systems and their solutions
  • Knowledge of irrational numbers and their properties
  • Familiarity with Cramer's Rule for solving systems of equations
  • Basic skills in manipulating algebraic expressions involving square roots
NEXT STEPS
  • Study the application of Cramer's Rule in solving linear systems with irrational coefficients
  • Learn about linear dependence and its implications for the uniqueness of solutions
  • Explore methods for expressing irrational numbers in algebraic solutions
  • Investigate the limitations of calculators in solving equations with irrational numbers
USEFUL FOR

Students studying algebra, mathematics educators, and anyone interested in the precise solutions of linear systems involving irrational numbers.

adc85
Messages
34
Reaction score
0
One of the questions on a handout was this:

Solve the following linear system:

[2 1 : 4 ]
[2*sqrt of 3 sqrt of 3 : 4*sqrt of 3]

A) Precisely B) With a calculator.

Since this linear system contains irrational numbers, how would you solve it "precisely"? How would the answer be any different than if a calculator was used? Do I just leave alone the irrational square root terms and express the answer like that? Thanks for any help.
 
Physics news on Phys.org
adc85 said:
One of the questions on a handout was this:

Solve the following linear system:



A) Precisely B) With a calculator.

Since this linear system contains irrational numbers, how would you solve it "precisely"? How would the answer be any different than if a calculator was used?
Your solution may contain irrational numbers. Most calculators only display rational approximations (as some finite decimal).
Do I just leave alone the irrational square root terms and express the answer like that?
Unless you can find another way of expressing them that is not an approximation, yes. :)
 
Maybe the professor is trying to show you what happens when you solve a system like that with a calculator. I don't know what happens when you try to solve that with a calculator, but since the above works for all x,y in R I would guess that the calculator can't represent this solution or something. The professor might therefore be trying to show you the dangers of using a calculator to solve systems of equations. Just a guess :/

EDIT: Why it works for all x,y in R--multiply top by -sqrt(3)
 
If you multiply the first equation by sqrt(3), you will see that the two become identical. This means that they are linearly dependent and there will be NO unique solution. There will actually be an infinite number of solutions. Maybe that is what your prof was trying to show.
 
Parth Dave, so what about the calculator part? Would it hold true for the calculator part too? How would I know?

Also, if I had problem like:

[4*sqrt of 3 5 : 2 ]
[5 sqrt of 13 : 1 ]

What approach do I need to take here (same subject on solving precisely and solving by calculator)? I have to solve using determinants. He never covered this in class yet it's on the homework.
 
Well if you have to solve it using determinants then you probably need to solve it using Cramer's rule.
 
I tried that with the precise method by leaving alone the irrational numbers (keeping the square roots the way they are). And I end up with this really really long term that just doesn't seem right you know? Thanks for your help though.
 

Similar threads

Replies
6
Views
1K
  • · Replies 22 ·
Replies
22
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
3
Views
807
Replies
10
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
4
Views
2K