How Do You Solve the Diffraction Intensity Problem with Different Units?

[Precursor]

Homework Statement

[PLAIN]http://img714.imageshack.us/img714/8205/65617184.jpg

Homework Equations

$$I = I_{0} [\frac{sin[\pi a(sin\theta)/\lambda]}{\pi a(sin\theta)/\lambda}]^{2}$$

The Attempt at a Solution

Here is my attempt:

$$I = I_{0} [\frac{sin[\pi (50)(sin\1)/632]}{\pi (50)(sin1)/(632)}]^{2}$$

$$I = 3.00*10^{-4} I_{0}$$

However, this solution is not one of the options. Where did I go wrong? Is it the units?

 

[ehild]

What is the width of the slit?

ehild

 

[Precursor]

The width of the slit is 50.0 $\mu m$

 

[Beer-monster]

Is your wavelength in nanometers or micrometers?

 

[ehild]

The width of the slit is 50.0 $\mu m$

The width is measured in micrometers, but the wavelength is given in nanometers. Use the same units for both.

Do not forget that the argument of the outer sine function is in radians.

ehild