How Do You Solve the Tortoise & Hare Race Problem?

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SUMMARY

The Tortoise and Hare race problem involves calculating the time and distance of a race where a tortoise runs at 0.10 m/s and a hare runs at 2.0 m/s but takes a 5-minute rest. The tortoise wins by 0.40 m. The equations used to solve the problem are dt - 0.40 = (20)(0.10)(t - 300) for the hare and d = 0.10t for the tortoise. Setting the distances equal allows for the determination of the race duration and length.

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  • Understanding of basic kinematics equations
  • Knowledge of algebraic manipulation
  • Familiarity with speed, distance, and time relationships
  • Ability to convert time units (e.g., minutes to seconds)
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aznbaby
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Homework Statement


A tortoise can run with a speed of 0.10 m/s, and a hare can run 20 times as fast. In a race, they both start at the same time, but the hare stops to rest for 5.0 minutes. The tortoise wins by a shell (40 cm).
(a) How long does the race take? (s)
(b) What is the length of the race? (m)

Homework Equations



d= distance
s= speed
t= time
subscripts;
h=hare
t=tortoise

dh=sh x th
dt=st x tt


The Attempt at a Solution



i have these two equations:

dt-0.40=(20)(0.10)(t-300)

d=0.10t

how do i set them equal to each other
or how do i solve them? i have no clue...
 
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Welcome to PF!

Hi aznbaby! Welcome to PF! :smile:
aznbaby said:
i have these two equations:

dt-0.40=(20)(0.10)(t-300)

d=0.10t

how do i set them equal to each other
or how do i solve them? i have no clue...

(shouldn't the second equation also be dt?)

Just put the two d's equal :wink:

which gives you t = … ? :smile:

(though personally I'd have defined dh = (20)(0.10)(t-300), and then put dh = dt - 0.40)
 

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