How Do You Solve This Bernoulli Differential Equation?

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SUMMARY

The discussion focuses on solving a Bernoulli differential equation represented by the formula \(\frac{dy}{dx} - \frac{1}{x}y + \frac{1}{y^2}x = 0\). Participants detail the step-by-step approach to solving the equation, including transforming it into a more manageable form and addressing typographical errors in the original equations. The conversation also touches on a related ordinary differential equation (ODE) where the solution involves manipulating derivatives and integrating to find the function \(f(x)\). The final solution is expressed as \(z = 3x^2 + C(x^3)\).

PREREQUISITES
  • Understanding of Bernoulli differential equations
  • Familiarity with ordinary differential equations (ODEs)
  • Knowledge of derivatives and integration techniques
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the general solution methods for Bernoulli differential equations
  • Learn about the application of integrating factors in ODEs
  • Explore advanced techniques for solving nonlinear differential equations
  • Practice solving various forms of ordinary differential equations
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Mathematics students, educators, and professionals involved in differential equations, particularly those focusing on Bernoulli and ordinary differential equations.

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\frac{dy}{dx} - \frac{1}{x}*y + \frac{1}{y^2}*x = 0

This is a bernoulli differential equation which follows the following procedure
http://en.wikipedia.org/wiki/Bernoulli_differential_equation
Can someone provide the full steps because somewhere I am mistaken?
 
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See attachment :
 

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Thank you a lot. One more question:
In ODE I reach in a place where i have that
\frac{dz}{dx}*x^3- 3x^2*z + 3x^4 = 0

I cannot find the derivatve on that
 
Last edited:
I cannot find the derivatve on that
I cannot understand what you mean : The derivative of what function ?
Well, the equation is
x(dz/dx)-3xz = -3x²
So , solving x(dZ/dx)-3x = 0 leads to Z = C*(x^3)
Remplace C by f(x)
then z = f(x)*(x^3)
dz/dx = (x^3)*(df/dx) +3*x² f
x( (x^3)*(df/dx) +3*x² f ) -3x (x^3)*f = -3x²
(x^4)*(df/dx) = -3x²
df/dx = -3/x²
f = (3/x) + C
z = 3 x² + C (x^3)
 
x(dz/dx)-3xz = -3x²
how did you find that?
 
Sorry, there was a typo. The correct equation is
x(dz/dx) - 3z = -3x²
and there was other typo in my message #4.
As a consequence, my message #4 is wrong.
Nevertheless, it shows the method to solve this kind of equations.
 

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