How do you solve this equation (involving exponentials)?

[xllx]

Homework Statement

0=x(e^-x)

Homework Equations

The Attempt at a Solution

Well as x is a multiple that leaves:
0=e^-x
so does x=0?

Any help at all would be greatly appreciated. Many Thanks.

 

[Mark44]

If a*b = 0 then a = 0 or b = 0.
For your equation, either x = 0 or e^-x = 0.
Clearly, x = 0 is a solution of your equation. Are there any values of x for which e^-x = 0?

 

[xllx]

Are there any values of x for which e^-x = 0?

Well wouldn't x be infinity in that case?
But this question is referring to co-ordinates of a turning point so surely a turning point can't be infinity?

The original equation was y=(x^2)(e^-x)
Which I differentiated into:
dy/dx=x^2(-e^-x)+(e^-x)2x
Which I factorised into:
dy/dx=x(e^-x)[-x+2]

And as dy/dx=0 for turning points then:
0=x(e^-x)[-x+2]
So x=2 and 0=x(e^-x)

Is this all right?

Thankyou so much.

 

[Mark44]

So x = 2 or x = ?

 

[xllx]

Is it zero?

 

[Mark44]

Yes.

 

[xllx]

Thankyou!