Macarenses
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How does one prove that for w≠+-1 , w a complex number, there are exactly 2 solutions to the equation w=0.5(z+1/z)? I'm at a total loss here. Could someone clue me in on this one?
How Do You Solve w=0.5(z+1/z) for Complex w?
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ramsey2879
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What if you multiplied each side by 2z?Macarenses said:How does one prove that for w≠+-1 , w a complex number, there are exactly 2 solutions to the equation w=0.5(z+1/z)? I'm at a total loss here. Could someone clue me in on this one?
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The best way to prove there are two solutions is to find them! That is what ramsey2879 is suggesting.
ramsey2879
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I do believe that the quadratic formula will work for equations with complex coefficients even if it is not clear (at least to me) how to find the square root of a complex number. Just write the solution out in the radical form simplified as far as posible.HallsofIvy said:The best way to prove there are two solutions is to find them! That is what ramsey2879 is suggesting.
lostcauses10x
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Do a internet search: complex numbers solve square root
TheBonobo4
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w=0.5(z+1/z)
w=0.5z+0.5/z
wz=0.5z^2+0.5
0.5z^2+0.5-wz=0
If you could substitute a value of either w or z you could work out the other using Quadratic Formula
x = (-b +- sqrt(b^2-4ac))/2a
Other than this, I can't see how you solve it since you have 2 unknowns. Either way you have a squared value for z so z has 2 solutions.
Sorry if I was no help, this is my first post here as I just joined today. :)
w=0.5z+0.5/z
wz=0.5z^2+0.5
0.5z^2+0.5-wz=0
If you could substitute a value of either w or z you could work out the other using Quadratic Formula
x = (-b +- sqrt(b^2-4ac))/2a
Other than this, I can't see how you solve it since you have 2 unknowns. Either way you have a squared value for z so z has 2 solutions.
Sorry if I was no help, this is my first post here as I just joined today. :)
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