How Do You Sum the Components of Vectors in Three Dimensions?

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To sum the components of vectors C and D in three dimensions, the x, y, and z components must be added separately. The components are given as Cx = 8.10, Cy = -5.40, Cz = -7.90, Dx = 4.40, Dy = -2.50, and Dz = 4.50. The confusion arises around the z component, particularly regarding its negative value and whether it indicates direction. The negative sign indicates direction in the three-dimensional space, and z does not represent a hypotenuse but rather a distinct component in the vector sum. Understanding these components is essential for correctly calculating the resultant vector.
JVeazie
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Homework Statement


[/B]
Given the following vector components of vectors C and D:
Cx = 8.10, Cy = -5.40, Cz = -7.90, Dx = 4.40, Dy = -2.50, Dz = 4.50,
find the x, y, z components of their sum.

Homework Equations



No relevant equations that I know of...[/B]

The Attempt at a Solution



I am lost completely. I do understand using (x,y) components, as well as use of the Pythagorean theorem for right triangles, etc...
The z component is throwing me off completely. Do I use the (-) as an indication of direction? Does Z represent a hypotenuse?
Im so confused.
 
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JVeazie said:

Homework Statement


[/B]
Given the following vector components of vectors C and D:
Cx = 8.10, Cy = -5.40, Cz = -7.90, Dx = 4.40, Dy = -2.50, Dz = 4.50,
find the x, y, z components of their sum.

Homework Equations



No relevant equations that I know of...[/B]

The Attempt at a Solution



I am lost completely. I do understand using (x,y) components, as well as use of the Pythagorean theorem for right triangles, etc...
The z component is throwing me off completely. Do I use the (-) as an indication of direction? Does Z represent a hypotenuse?
Im so confused.

Z represents that you're working in ##\mathbb{R}^3##, do you know what this means?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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