Trying to separate vector into x and y components

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SUMMARY

The discussion focuses on separating a vector into its x and y components, specifically the vector \(\overrightarrow{a} = (58 \, \text{m/s}^2, 40^\circ \text{ below positive } x \text{-axis})\). The initial calculations provided were incorrect due to a sign error in the x and y components. The correct components are \(a_x = -37\) and \(a_y = 44\), expressed as "-37,44". The importance of drawing a diagram to visualize the vector orientation is emphasized.

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Homework Statement


##\overrightarrow{a} = (58m/s^2, 40°## below positive ##x## - axis)
Find the ##x##- and ##y##-components of the vector.
Express your answers using two significant figures. Enter your answers numerically separated by a comma (##a_x,a_y##).

Homework Equations


None I can think of.

The Attempt at a Solution


I've already done this all out on paper, it seems like simple enough trig, and should be:
##a_x = -58sin(40) = 58sin(320) = -37## (correct to two significant figures)
##a_y = 58cos(40) = 58cos(320) = 44## (correct to two significant figures)
Therefore, the components as a comma separated list should be "##-37,44##".

Yet this is not the answer. What am I doing wrong?

Edit: I realized after drawing it out that I switched the signs for ##x## and ##y##. I'm a fool, please disregard this thread.
 
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