How Do You Tackle This Modulus Equation Challenge?

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Homework Help Overview

The discussion revolves around solving the modulus equation |12x -9| = |3 -4x| +2x -1, focusing on the properties of absolute values and the conditions under which they change. Participants are exploring how to set up the equation based on the behavior of the absolute values involved.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss whether to consider both positive and negative cases for the absolute values. There is an exploration of how to determine when each expression inside the absolute values is positive or negative, and how that affects the setup of the equation.

Discussion Status

The conversation is ongoing, with participants providing insights into the conditions for the absolute values and discussing the implications of those conditions on the equation. Some guidance has been offered regarding the approach to take based on the value of x relative to 3/4, but no consensus has been reached on the specific steps to solve the equation.

Contextual Notes

Participants note a lack of familiarity with modulus functions, which may affect their understanding of the problem setup. There is also mention of different cases to consider based on the value of x, indicating a need for clarity on how to handle the absolute values in the equation.

Azure Skye
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I have to solve the equation: |12x -9| = |3 -4x| +2x -1

I was wondering if it's supposed to be like:

12x -9 = 3 -4x +2x -1 and -12x +9 = 3 -4x +2x -1 ?

Or am I supposed to consider the positive and negative of 3 -4x also?
I didn't attend lessons for this and I know little about modulus functions. :/
 
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Actually what you do is you find what values of x make one of the absolute values more than zero, so let's do that now:

[tex]12x-9\geq 0[/tex]

[tex]x\geq 3/4[/tex]

Therefore for all [tex]x\geq 3/4[/tex] that inequality is positive.

For the other inequality, at x=3/4 we have 3-4x=0 and for any [tex]x\geq 3/4[/tex] we have [tex]3-4x\leq 0[/tex] So this means for all [tex]x\geq 3/4[/tex] we have the first inequality is more than zero, and the second is less than zero (so we take the negative of it). And things are just reversed when we consider when [tex]x<3/4[/tex].
 
So does the inequality formed from |12x -9| applies to |3 -4x|?

Then do I end up with something like 12x -9 = 0 +2x -1?
 
Yes it does apply to the other inequality.

If you have |a|=|a+1| then you need to look at one of the absolute values. For the first, when [itex]a\geq 0[/itex] then you leave that as a, when [itex]a<0[/itex] you change that to -a (since the negative of a negative number is positive). But for the other inequality, when [itex]a+1\geq 0[/itex] or in other words, [itex]a\geq -1[/itex] then that absolute value is positive and thus left as a+1, so when [itex]a<-1[/itex] it becomes -(a+1)=-a-1.

So this means when a<-1 we have both absolute values are negative so we solve -(a)=-(a+1) and when a>0 we have both are positive, so we solve a=a+1. What about for [itex]-1< a< 0[/itex]? Well we have that the first is negative, and the second is positive so we solve -a=a+1

The same idea applies to your problem, so no, you don't solve 12x-9=0+2x-1. Use the idea of cases when x>3/4 and x<3/4 (this problem is easier since you only need two cases). Also, you can add in the value of x=3/4 later or just include it into each inequality, it doesn't really matter.
 
Does this means that because |12x -9| is x > 3/4 and |3 -4x| is x< 3/4, when 12x -9 is positive, 3 -4x is negative and vice versa?

So when I consider x > 3/4, I get
12x -9 = 4x -3 +2x +1
x = 7/6

Is that correct or wrong?
 

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