How do you write chemical formulas for ionic compounds?

  • Thread starter Thread starter ncmm16
  • Start date Start date
  • Tags Tags
    Formulas
Click For Summary
SUMMARY

This discussion focuses on writing chemical formulas for ionic compounds, specifically combining cations and anions to achieve a neutral charge. The examples provided include the combination of sulfate (SO42-) with aluminum (Al3+) and dichromate (Cr2O72-) with aluminum. The method involves determining the least common multiple (LCM) of the charges to balance them, resulting in formulas such as Al2(SO4)3 and Al2(Cr2O7)3. Simplification of charges is also emphasized for clarity in subscripts.

PREREQUISITES
  • Understanding of ionic compounds and their charges
  • Basic knowledge of least common multiples (LCM)
  • Familiarity with chemical notation and subscripts
  • Elementary algebra skills for balancing equations
NEXT STEPS
  • Study the rules for naming ionic compounds
  • Learn about polyatomic ions and their charges
  • Practice writing formulas for various ionic compounds
  • Explore balancing chemical equations in more complex reactions
USEFUL FOR

Chemistry students, educators, and anyone seeking to understand the fundamentals of ionic compound formation and chemical notation.

ncmm16
Messages
3
Reaction score
0
So its the beginning of chemistry and I don't know how to make formulas. BUT its very important I learn now otherwise I will have a very hard year...

For ex:
It says, "Fill in the correct formulas for the given anion and cation."


SO2-4 and Al3+ (how do i combine those two to make a formula)


Another ex:
Al3+ and Cr2O2-7
PLEASE EXPLAIN HOW TO DO THESE.

Thanks so much for any help:)!
 
Chemistry news on Phys.org
The resulting molecule must be uncharged.
So if you have Al(3+) and SO4(2-) you need to find how many 3+ you need to combine with how many 2- to get zero.
This is just a least common multiple elementary school maths problem.
In this case the LCM is 6, so 2*(3+) and 3*(2-) =0 giving Al2(SO4)3
 
Write out the cation and the anion with their charges. For your second example, this would be written as Al^{3+}Cr_{2}O_{7}^{2-}. Then write the charge of the cation as the subscript of the anion, and vice versa, ignoring the plus and minus of course. It then looks like Al_{2}(Cr_{2}O_{7})_{3}. This is basically what mgb phys said, only it's a quicker (and many people starting chemistry find it easier) way to do it. It's also important to note that if you have charges like 4+ and 2-, you must simplify it to 2 and 1 when you write the subscripts.

EDIT: When I wrote the subscripts they came up as superscripts for some reason. Hopefully you can still tell what I meant.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 46 ·
2
Replies
46
Views
6K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
Replies
1
Views
4K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
3
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K