How Does a Capacitor Behave in a Simple Circuit?

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The discussion focuses on the behavior of a capacitor in a simple circuit consisting of a 3V power supply, a 5000uF capacitor, and a 200-ohm resistor. The time constant for the circuit is calculated as 1000 seconds using the formula T=RC. The charge on the capacitor at 3V is determined to be 15 coulombs, and the energy stored in the capacitor is calculated to be 22.5 joules using the formula E=1/2CV². A correction is noted regarding the initial current during discharge, emphasizing the need to relate current (i(t)) to charge (q(t)).

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Timiop2008
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A working circuit contains a 3V power supply, a 5000uF Capacitor, and a 200ohm resistor.

a) What is the time constant for the circuit?
b) What is the charge in coloumbs on the capacitor at a potential difference of 3V?
c) How much energy is stored on the Capacitor at a potential difference of 3V?
d) Calculate the initial value of the current when the fully charged capacitor starts to discharge through the resistor.

Attempt:
a) T=RC
= 200 X (5000X10-3)
=1000 seconds

b) Q=CV
Q = 5000X10-3 X3
= 15C

c) E=1/2CV2
E=1/2 X 5000X10-3 X 32
E = 22.5J

d) Q=Q0e-t/RC
 
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Timiop2008 said:
A working circuit contains a 3V power supply, a 5000uF Capacitor, and a 200ohm resistor.

a) What is the time constant for the circuit?
b) What is the charge in coloumbs on the capacitor at a potential difference of 3V?
c) How much energy is stored on the Capacitor at a potential difference of 3V?
d) Calculate the initial value of the current when the fully charged capacitor starts to discharge through the resistor.

Attempt:
a) T=RC
= 200 X (5000X10-3)
=1000 seconds

b) Q=CV
Q = 5000X10-3 X3
= 15C

c) E=1/2CV2
E=1/2 X 5000X10-3 X 32
E = 22.5J

d) Q=Q0e-t/RC
I think you did everything fine until the d) part. Currents are measured in amperes. What you wrote is the charge of the capacitor. How is i(t) related to q(t)? What you wrote is q(t).
How much is worth t when the capacitor starts to discharge?
 

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