How Does a Diverging Lens Affect Image Position and Size?

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SUMMARY

The discussion focuses on the optical principles governing image formation through a diverging lens. An illuminated arrow measuring 2 cm in height is positioned 108 cm from a diverging lens with a focal length of -36 cm. The calculated image position is -27 cm, indicating that the image is virtual and located on the same side as the object. The image height is determined to be 0.5 cm, demonstrating the reduction in size due to the lens's diverging properties.

PREREQUISITES
  • Understanding of lens formulas, specifically the thin lens equation.
  • Knowledge of optical principles related to virtual and real images.
  • Familiarity with the concept of magnification in optics.
  • Basic skills in algebra for solving lens-related equations.
NEXT STEPS
  • Study the thin lens equation and its applications in optics.
  • Explore the concept of magnification and its calculations for various lens types.
  • Learn about the differences between converging and diverging lenses.
  • Investigate real-world applications of diverging lenses in optical devices.
USEFUL FOR

This discussion is beneficial for physics students, optical engineers, and educators seeking to deepen their understanding of lens behavior and image formation in optics.

araicktavio
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1.An illuminated arrow 2 cm high is placed 108 cm from a diverging lens of focal length-36 cm. Find the position and height of the image.
The answers are supposed to be -27 cm and 0.5 cm.
Any help would be great.
Thanks:!)

 
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