How Does a Hawk's Acceleration Change When Speed Increases in Circular Motion?

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Homework Help Overview

The discussion revolves around a physics problem involving a hawk flying in circular motion, specifically examining how its acceleration changes as it increases speed while maintaining a constant radius. The problem involves concepts of centripetal and tangential acceleration.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the relationship between tangential and centripetal acceleration, questioning how to calculate the resultant acceleration when speed increases. There is a discussion about the dependence of normal acceleration on time as speed changes.

Discussion Status

Participants are actively engaging with the problem, offering insights into the nature of the accelerations involved. There is recognition that the magnitude of acceleration is a function of time, and some express concerns about the clarity of the problem statement.

Contextual Notes

There is an assumption that the calculation of acceleration may be intended at a specific moment in time, which raises questions about the problem's design and clarity.

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Circular Motion Question!

Homework Statement




A hawk flies in a horizontal arc of radius 18.3 m at a constant speed of 2.3 m/s.
It continues to fly along the same horizontal arc but increases its speed at the rate of
1.56 m/s2. Find the magnitude of acceleration under these new conditions.
Answer in units of m/s2.

Homework Equations




A=V^2/r

The Attempt at a Solution


The centripetal Acceleration is .29m/s2, and I stumped. Any help?
 
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When the speed starts increasing, there is a component along the arc (tangential acceleration of 1.56 m/s2) and a component towards the center (centripetal acceleration). These two components are perpendicular to each other. Can you find the magnitude of the total acceleration?
 


Yes the magnitude is the resulatant of the tangential and normal(centrepital) accelerations, but the magnitude should be a function of time. This is because your tangential acceleration is causing the velocity to increase. Hence even though your tangential acceleration is constant your normal acceleration will increase with time since a=(v^2)/r. So your normal acceleration a(t)=(v(t)^2)/r where v(t) is a linear function that can be determined from the formulas for constant acceleration.
 


kjohnson said:
Yes the magnitude is the resulatant of the tangential and normal(centrepital) accelerations, but the magnitude should be a function of time. This is because your tangential acceleration is causing the velocity to increase. Hence even though your tangential acceleration is constant your normal acceleration will increase with time since a=(v^2)/r. So your normal acceleration a(t)=(v(t)^2)/r where v(t) is a linear function that can be determined from the formulas for constant acceleration.

Indeed the magnitude is a function of time. However, since the problem does not specify when the magnitude is to be calculated, one can only assume that is at time t = 0, i.e. when the tangential acceleration is "turned on", but before the speed can change appreciably. In my opinion this is not a well-crafted problem.
 

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