How Does a Neutral Metal Ball Interact with a Nearby Point Charge?

AI Thread Summary
The discussion revolves around calculating the attractive force between a neutral metal ball and a nearby point charge, while also determining the work required to move the charge to infinity. Key points include the understanding that the electric field inside the conductor must vanish and that the potential remains constant on the surface of the sphere. The method of images is referenced, highlighting that no induced charge occurs since the sphere is not grounded, leading to charge movement within the sphere without changing its net charge. The conversation also touches on the necessity of introducing an image charge to maintain the boundary conditions, ultimately suggesting that the image charge should be placed at the center of the sphere. The participants find clarity through shared resources, facilitating a better grasp of the problem.
funoras
Messages
21
Reaction score
0

Homework Statement


Find the attractive force between a neturally charged metal ball of radius r and a point charge q, located a distance l from the center of the ball. Also find the work needed to move the charge to infinity. The ball is not grounded.


Homework Equations


-


The Attempt at a Solution


I'm stuck on this one. I know that potential must be constant and the electric field must vanish inside the conductor (ball) but that's it.
 
Physics news on Phys.org
have you learned about the method of electrical images?
how does that apply to the situation of your problem if the sphere is grounded?
what is the relation between net induced charge and the image charge?
 
Yes, i know how to solve this problem using method of images if the sphere is grounded. The induced charge would be q_i=-qr/l. But in this case there is no charge induced,since the sphere is not grounded, the charges just move inside the sphere, but the net charge still remains zero.
 
the boundary condition obviously is a constant potential on the sphere surface.
that you can achieve by the image charge(say, Q) at the same location as that in the case of grounded sphere.
but the net image charge must be equal to total induced charge(a consequence of gauss's law).so you need to put another charge -Q inside sphere such that total image charge is zero.
you should now be able to figure out the location of charge -Q.
 
it should be at the center of the sphere i guess ? in that case the potential at any point on the sphere will be q/4πε_0d , as expected
edit: didn't see that article you posted. it helped a lot. thanks! The rest is piece of cake.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
I was thinking using 2 purple mattress samples, and taping them together, I do want other ideas though, the main guidelines are; Must have a volume LESS than 1600 cubic centimeters, and CAN'T exceed 25 cm in ANY direction. Must be LESS than 1 kg. NO parachutes. NO glue or Tape can touch the egg. MUST be able to take egg out in less than 1 minute. Grade A large eggs will be used.
Back
Top