How does a thin sheet of aluminum impact capacitance in a circuit?

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Homework Help Overview

The discussion revolves around the impact of a thin sheet of aluminum placed between the plates of a capacitor on its capacitance. Participants are exploring the implications of introducing a metallic layer in terms of dielectric properties and capacitance calculations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply the concept of dielectric constants and capacitance formulas to determine the effect of the aluminum sheet. Some participants question how the introduction of a metallic plate alters the configuration of the capacitor and its effective capacitance.

Discussion Status

There is an ongoing exploration of different interpretations regarding the effect of the aluminum sheet on capacitance. Some guidance has been provided on considering the aluminum as two separate plates, leading to a comparison of net capacitance before and after its introduction.

Contextual Notes

Participants are working under the assumption that the area of the plates and the distance between them can be defined, but specific values or configurations are not provided. The discussion includes considerations of the dielectric properties of metals and how they relate to capacitance changes.

aimiit
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Homework Statement



As shown in the figure, a very thin sheet of aluminium in placed in between the plates of the condenser. Then the capacity
(a) Will increase (b) Will decrease (c) Remains unchanged (d) May increase or decreas

Homework Equations



Dielectric strength of a metal.

The Attempt at a Solution



Since dielectric constant for a metal is infinty, and the formula for capacitance is :
εoA/ d - t + \frac{t}{k}
If k = infinity, and t/k = t/infinity = 0.

Then we will be left with εoA/ d - t

Since denominator is decreasing, the value of C should increase. Therefore my answer is (a) Will increase.
But the correct answer is (d) May increase or decrease
 

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Look it at like this, plates of capacitor are metallic (generally) and you also introduced a metallic plate,

So you can assume 2 sides of introduced plate as two individual plates connected with a wire. So you get 2 series capacitors ...
 
How would that help?
 
That way you can find net capacitance and then compare the new and prevoius capacitances.

PS: forgot to mention this before, you can assume plate area as A and distance as d
New plate are after inserting plate will be (?) and the distance between plates of 2 new formed capacitors will be (?)
 

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