1. The problem statement, all variables and given/known data 2. Relevant equations C = q / voltage 3. The attempt at a solution OK. By Kirchoff's Voltage Law, we have: EMF - ( q / Capacitance)x - (q/Capacitance)y = 0 Now. I know that having the dielectric increases the capacitance of X, so the voltage drop across it is smaller, which is in accordance with D being the right answer. On the other side, I thought that the Charge Qy would have to increase to create a higher voltage drop across capacitor Y to compensate for the decreased voltage drop across capacitor X. However, the right answer says that the charges on the two capacitors are the same. Why is this the case? Thanks in advance for the help!