It sounds like you don't really have an understanding of what's going on, so I'll try to start at the beginning. When ionizing radiation impinges on ZnS, it excites electrons from the valence band to the conduction band of the material. The scintillation is the light emitted when these electrons fall back down into the valence band (or, to put it another way, when they recombine with the hole in the valence band). The band gap of ZnS is ~3.5eV, which is in the UV. This means that the photoemission from electron-hole recombination in ZnS is not visible. To make it visible, you add Ag impurities. These trap electron-hole pairs and recombine them at a lower energy, so that the emission from these recombination events ends up being blue light. A low concentration of silver ensures that 1) there's a pathway for photoemission that's smaller than the band gap energy, but 2) the silver atoms in general are far enough apart that they only weakly perturb the ZnS band structure and don't interact to produce unexpected states in the band gap.