How Does Angular Speed Affect Scale Readings on a Ferris Wheel?

  • Thread starter Thread starter will21
  • Start date Start date
  • Tags Tags
    Wheel
Click For Summary
SUMMARY

The discussion focuses on calculating the difference in scale readings experienced by a woman of mass m riding a Ferris wheel of radius R at a constant angular speed w. The difference in scale readings, denoted as “delta” F, is derived from the equations n1 = mg - mv²/R (top of the Ferris wheel) and n2 = mv²/R + mg (bottom of the Ferris wheel). When w = 0 rad/s, “delta” F equals zero, confirming that there is no difference in scale readings at rest. As w increases, the difference in scale readings increases, demonstrating the impact of angular speed on perceived weight.

PREREQUISITES
  • Understanding of angular motion and forces
  • Familiarity with Newton's second law of motion
  • Knowledge of centripetal acceleration
  • Basic algebra for solving equations
NEXT STEPS
  • Study the effects of angular velocity on centripetal force
  • Learn about the relationship between mass, weight, and acceleration due to gravity
  • Explore the concept of apparent weight in rotating systems
  • Investigate real-world applications of physics in amusement park rides
USEFUL FOR

Physics students, educators, and anyone interested in understanding the principles of rotational dynamics and their practical applications in engineering and amusement rides.

will21
Messages
1
Reaction score
0

Homework Statement



A woman of mass m rides in a Ferris wheel of radius R. In order to better understand physics, she takes along a bathroom scale and sits on it. Determine the difference in scale readings between the bottom and top of the Ferris wheel (“delta” F of scale) as a function of the constant angular speed of the ferris wheel (w),m,R,and g.

If w=0 rad/s, what should “delta” F of scale equal? Does your dunctoin agree with this observation?
If w was twice as large, what would happen to “delta” F of scale?

Homework Equations


mv^2/R
mg

The Attempt at a Solution


Top (n1): mg - mv^2/R
Bottom (n2): mv^2/R + mg
m = (n2 + n1)/2g

Not very sure...
 
Physics news on Phys.org
will21 said:

Homework Statement



A woman of mass m rides in a Ferris wheel of radius R. In order to better understand physics, she takes along a bathroom scale and sits on it. Determine the difference in scale readings between the bottom and top of the Ferris wheel (“delta” F of scale) as a function of the constant angular speed of the ferris wheel (w),m,R,and g.

If w=0 rad/s, what should “delta” F of scale equal? Does your dunctoin agree with this observation?
If w was twice as large, what would happen to “delta” F of scale?



Homework Equations


mv^2/R
mg



The Attempt at a Solution


Top (n1): mg - mv^2/R
Bottom (n2): mv^2/R + mg
m = (n2 + n1)/2g

Not very sure...
Your equations are correct, but solving for m does not give you the desired solution. The difference in the scale readings is (n2) - (n1), where (n2) and (n1) represent the scale readings at the bottom and top of the ferris wheel, respectively..
 
Yes, recall that what you are looking for is the change, and thus the difference, between the two quantities.
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
7K
Replies
12
Views
2K
Replies
3
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 4 ·
Replies
4
Views
11K
  • · Replies 6 ·
Replies
6
Views
5K
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
Replies
6
Views
7K
  • · Replies 3 ·
Replies
3
Views
3K