How does atmospheric dissipation affect UV light measurements?

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SUMMARY

The discussion focuses on the atmospheric dissipation of ultraviolet (UV) light, specifically examining how much power from a 280nm UV LED with a 1 mW output would reach a detector 100 meters away. The primary principle involved is Rayleigh scattering, which significantly impacts UV light transmission through the atmosphere. The Beer-Lambert Law is referenced as a potential resource for understanding the attenuation of light due to scattering and absorption in the atmosphere.

PREREQUISITES
  • Understanding of Rayleigh scattering principles
  • Familiarity with the Beer-Lambert Law
  • Knowledge of UV light properties, specifically at 280nm
  • Basic concepts of optical power measurement
NEXT STEPS
  • Research the Beer-Lambert Law in detail for UV light applications
  • Explore Rayleigh scattering equations and their implications for UV light
  • Investigate atmospheric conditions that affect UV light transmission
  • Learn about UV LED characteristics and their measurement techniques
USEFUL FOR

Researchers in atmospheric science, optical engineers, and anyone involved in UV light measurement and analysis will benefit from this discussion.

ykaravas
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I am looking around for some sort of equation regarding optical power dissipation of light (ultraviolet light in particular) in the atmosphere but i cannot find anything. I know that UV light obeys Rayleigh scattering but I don't know much else. I'm trying to figure out for example, if I shined a UV LED of 280nm wavelength and power output of 1 mW and tried to measure it 100 meters away, how much power of the original 1 mW would reach the detector. In essence, how much of the UV light is "lost" due to atmospheric dissipation.

Can anyone refer me to a formula or a link which has this information?

Thank you.
 
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