How Does Charge Affect Motion in Outer Space?

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SUMMARY

The discussion focuses on the physics of motion and electric forces in outer space, specifically involving a 0.25 kg ball with a charge of +4/K C shot towards a +0.5 C charged ball. The primary principles to apply are Newton's Second Law (F=ma) and the electric force equation (F(electric) = KQq/r^2). The participant calculated an acceleration of -0.32 m/s² but questioned the validity of their displacement calculation, which yielded an unreasonable distance of 625 m. Clarification on the charge units and the behavior of the charged balls in motion was also sought.

PREREQUISITES
  • Understanding of Newton's Second Law (F=ma)
  • Familiarity with electric force equations (F(electric) = KQq/r^2)
  • Knowledge of kinematic equations for motion
  • Basic concepts of electric charge and its effects on motion
NEXT STEPS
  • Study the implications of electric charge on motion in physics
  • Learn about kinematic equations and their applications in non-constant acceleration scenarios
  • Explore the concept of electric fields and forces between charged objects
  • Investigate the effects of large charges on physical objects and their stability
USEFUL FOR

Students studying physics, particularly those focusing on electromagnetism and motion, as well as educators seeking to clarify concepts related to charged particles and their interactions in space.

halo168
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Homework Statement


In outer space, a ball with mass 0.25kg and charge +4/K C is shot from 5m towards a +0.5C charged ball with an initial velocity of 20 m/s
  1. What main Physics principle should be used to solve this problem?
  2. What is the closest the small ball will get to the large one?
  3. What is the velocity and acceleration at this position?

Homework Equations


F=ma
vf=v0+2ax
F(electric) = KQq/r^2 where K = 9*10^9 Nm^2/C^2

The Attempt at a Solution


  1. I should use Newton's Second Law because by using F = ma, I could find a, then substitute into the 1D equation for displacement to solve for how far the 0.25kg ball travels.
  2. I got a=F/m = -0.32 m/s^2 and substituted into the equation vf=v0+2ax (I made vf=0) to find x. My answer was 625 m which is not reasonable.
  3. I couldn't find the answer without a correct answer from the second question.
 
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It is not clear whether the second ball is free to "recoil" or is somehow fixed in space.

Not sure what the units /K C means.

0.5 C is a HUGE amount of charge for a ball to have. (That's enough charge to blow the ball apart.)

Do you expect the acceleration of the 0.25 kg ball to remain constant as it approaches the other ball?

The equation vf=v0+2ax is not correct. It looks similar to an equation that is only valid for constant acceleration.
 
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