How Does Current Affect Magnetic Field at the Center of Two Wires?

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SUMMARY

The magnetic field at the center point between two parallel wires carrying currents of 2.00 A and 8.60 A can be calculated using the Biot-Savart Law. The formula B = (μ₀I)/(2πr) is applied, where μ₀ = 4π x 10^-7 T·m/A, r = 30.0 mm, and I represents the current. The calculated magnetic fields for each wire are B₁ = 1.34 x 10^-5 T and B₂ = 5.74 x 10^-5 T, resulting in a total magnetic field of B_total = 7.08 x 10^-5 T. The solution confirms the correct application of the Biot-Savart Law for this scenario.

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[SOLVED] Magnetic Field of Two Wires

Homework Statement



http://img80.imageshack.us/img80/5625/jonesj2qm4.gif

If r = 30.0 mm, i = 2.00 A, and i' = 8.60 A, what is the magnitude of the magnetic field at the center point?

Homework Equations



B=([tex]\mu[/tex][tex]_{0}[/tex]I)/(2pi*r)

The Attempt at a Solution



I applied biot-savart's law to i and i', and added them together.

For B_i:

(4pi*10^-7*2)/(2pi*.03) = 1.34*10^-5

For B_i':
(4pi*10^-7*8.6)/(2pi*.03) = 5.74*10^-5

B_center = B_i + B_i' = 7.08*10^-5

Which is not correct. I'm pretty much sure my method at solving the problem is completely wrong. I just don't know what exactly is the right steps to take. Any help would be appreciated.
 
Last edited by a moderator:
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biot-savart for a loop is u*2*pi*I/4*pi*R, which simplifies to u*I/2*R.. you're only looking for half a loop so 1/2 * that is equal to u*I/4*R ..

The total mag field would thus be: u*I'/4*R + u*I/4*R

u = 4*pi*10^-7, by the way.
 
Last edited:
Ah, thanks! Got it.
 

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