How Does Curvature Density Parameter Affect Universe Flatness?

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Discussion Overview

The discussion revolves around the effects of the curvature density parameter, Ωk, on the overall density parameter of the universe, Ωuniverse, particularly in the context of whether a negative value for Ωk can influence the sign of Ωuniverse. Participants explore the definitions and implications of these parameters within cosmological models.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • Some participants assert that for a flat universe, Ωuniverse must equal 1, and question how a negative curvature index, Ωk, affects this relationship.
  • Others clarify that Ωk is defined as 1 - (ΩM + ΩΛ + ΩR), suggesting that its value is not limited to 0, 1, or -1, and that a negative Ωk indicates positive curvature.
  • Several participants emphasize that the sum of the Ω parameters must equal 1, implying that all components contribute to the total density of the universe.
  • Some argue that interpreting a positive curvature as contributing negatively to the density parameter is problematic, as it could suggest that other components exceed 100% of the total density.
  • There is a discussion about the concept of negative percentages in quantum mechanics and whether such a notion could apply to cosmology, with differing views on the validity of this comparison.
  • Participants note that the curvature density parameter, Ωk, serves more as an indicator of deviation from flatness rather than a direct measure of density.

Areas of Agreement / Disagreement

Participants express differing interpretations of how the curvature density parameter interacts with the overall density parameter, leading to unresolved questions about the implications of negative values and the definitions involved.

Contextual Notes

There are limitations in the assumptions made regarding the definitions of the density parameters and their implications for curvature, which remain unresolved in the discussion.

Ranku
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For a flat universe, density parameter Ωuniverse=1. How does negative signage of a constituent density parameter, such as that of curvature index Ωk, which can be 0,1,-1 affect the signage of Ωuniverse? If Ωk were to be converted to its energy density, which is much less than the energy density of the other constituents, and even if Ωk = -1, would Ωuniverse = -1?
 
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If you include ##\Omega_k## in the sum of Omegas you get 1 by definition. Regardless of the curvature.
 
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Ranku said:
How does negative signage of a constituent density parameter, such as that of curvature index Ωk, which can be 0,1,-1 affect the signage of Ωuniverse?
In addition to what was explained by Orodruin, it is worth clarifying that the "curvature density parameter" ##\Omega_k## is, by definition, equal to 1-(##\Omega_M##+##\Omega_\Lambda##+##\Omega_R##), so its value is not restricted to being 0, 1 or -1. In fact, with that definition, a negative value of ##\Omega_k## implies a positive curvature of the universe.
 
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Orodruin said:
If you include ##\Omega_k## in the sum of Omegas you get 1 by definition. Regardless of the curvature.
Put another way, each of the ##\Omega## parameters is normalized so that the total adds up to 1. Saying that the sum of the ##\Omega## parameters is 1 is equivalent to saying that all of the components have to add up to 100% of the total.
 
ohwilleke said:
Saying that the sum of the ##\Omega## parameters is 1 is equivalent to saying that all of the components have to add up to 100% of the total.
It seems to me that this interpretation is not entirely correct because it would imply that, for example, a positive curvature contributes negatively to the density parameter, while dark energy, mass and radiation, added together, contribute more than 100% of the total.
 
Jaime Rudas said:
It seems to me that this interpretation is not entirely correct because it would imply that, for example, a positive curvature contributes negatively to the density parameter, while dark energy, mass and radiation, added together, contribute more than 100% of the total.
Negative percentages are common in quantum mechanics. Why not cosmology too?
 
Jaime Rudas said:
it would imply that, for example, a positive curvature contributes negatively to the density parameter
Yes, that's correct. The "density parameter" is not the same thing as actual density. It is just another way of organizing the math.
 
ohwilleke said:
Negative percentages are common in quantum mechanics. Why not cosmology too?
"Negative percentages" is only a workable description of things that occur in QM if you adopt an interpretation of that term that has no counterpart in a classical theory. So this response is not a valid one.
 
PeterDonis said:
Yes, that's correct. The "density parameter" is not the same thing as actual density. It is just another way of organizing the math.
The "curvature density parameter" ##\Omega_k## is more of an indicator of how far from flatness a space is, than a true indicator of density.
 
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Jaime Rudas said:
The "curvature density parameter" ##\Omega_k## is more of an indicator of how far from flatness a space is, than a true indicator of density.
Yes.
 

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