Spacetime curvature and curvature index

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Discussion Overview

The discussion revolves around the relationship between spacetime curvature, represented as a tensor, and the curvature index of space (k), which can take values of +1, 0, or -1. Participants explore how these concepts relate to the cosmological constant (Λ) and the implications for the fate of the universe.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • Some participants assert that the presence of the cosmological constant leads to a flat spacetime universe with Ω = 1, while k can take any value regardless of the sign of Λ.
  • It is noted that spacetime curvature is a tensor, whereas the curvature index is a normalized description of curvature for a homogeneous and isotropic spatial hypersurface.
  • Some participants question how spacetime curvature and curvature index can differ while both describe the curvature and fate of the universe.
  • There is a claim that if Ω = 1, then k must equal 0, and that the fate of the universe cannot be determined without knowing how energy content is distributed among its components.
  • Another participant emphasizes that Ω is not the spacetime curvature but rather the ratio of energy density to critical energy density, which is defined as the energy density at which k = 0.

Areas of Agreement / Disagreement

Participants express differing views on the relationship between Ω, k, and the fate of the universe, with some asserting a correlation while others argue that they are fundamentally different concepts. The discussion remains unresolved regarding the implications of these relationships.

Contextual Notes

Participants highlight the need for clarity on how energy content affects the relationship between Ω and k, indicating that assumptions about energy distribution are crucial to understanding the fate of the universe.

Ranku
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TL;DR
What is the difference between spacetime curvature and curvature index of space?
The presence of the cosmological constant produces a flat spacetime universe with Ω = 1. There is also the curvature index of space k, which can be +1, 0, -1. But it is possible to have any of these values of k with Λ > 0 or Λ < 0. How is the curvature of spacetime determined by Λ different from that of the curvature index of space k?
 
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Spacetime curvature is a tensor. The curvature index is a normalised description of the curvature of a homogeneous and isotropic spatial hypersurface.
 
Orodruin said:
Spacetime curvature is a tensor. The curvature index is a normalised description of the curvature of a homogeneous and isotropic spatial hypersurface.
Could you elaborate a bit more, in terms of how is it that spacetime curvature and curvature index of space don't have to agree, and yet each is supposedly uniquely describing the curvature and fate of the universe?
 
They do not have to agree because they are completely different things.
 
Orodruin said:
They do not have to agree because they are completely different things.
So, with Ω = 1, which describes a flat universe, and suppose k= +1, which describes a closed universe, what would be the fate of such a universe?
 
If ##\Omega = 1##, then ##k = 0##. You cannot say what is the fate unless you know how the energy content splits into components.
 
Orodruin said:
If ##\Omega = 1##, then ##k = 0##. You cannot say what is the fate unless you know how the energy content splits into components.
If Ω = 1, then k = 0, then that implies a consistent correlation, even if they are "completely different things". I am trying to understand that.
 
Ranku said:
If Ω = 1, then k = 0, then that implies a consistent correlation, even if they are "completely different things". I am trying to understand that.
##\Omega## is not the spacetime curvature. It is the energy density divided by the critical energy density. The critical energy density is defined as the energy density at which ##k = 0##.
 

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