How Does Dancer Movement Affect the Center of Gravity on a Dance Floor?

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SUMMARY

The discussion focuses on calculating the center of gravity for a dance floor with dimensions 19 m by 23 m and a mass of 1600 kg, with three dance couples each weighing 150 kg. The initial y-coordinate of the center of gravity was correctly calculated as 12.34 m. However, the participant encountered an error in calculating the new x-coordinate after one couple moved 10 m to the right, mistakenly using 1600(x-8) instead of the correct 1600(x-9.5), leading to an incorrect result of 8.366 m.

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lilaznjewel
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Homework Statement


Given: A flat dance floor of dimensions ℓx =
19 m by ℓy = 23 m and has a mass of M =
1600 kg. Use the bottom left corner of the
dance floor as the origin. Three dance couples,
each of mass m = 150 kg start in the top left,
top right, and bottom left corners.
What is the initial y coordinate of the cen-
ter of gravity of the dance floor and three
couples?
Answer in units of m.

The couple in the bottom left corner moves
ℓx = 10 m to the right. What is the new x
coordinate of the center of gravity?

Homework Equations


xcm =
m1x1 + m2x2/
m1 + m2

The Attempt at a Solution



for the first part I did 1600(y-11.5)+150(y-23)+150(y-0)+150(y-23)=0
and solved for y and I got 12.34
and I got it right

my problem is I did the exact same thing for the next part just you know used the X coordinates and moved (0,0) to (10,0)
1600(x-8)+150(x-0)+150(x-10)+150(x-19)=0
I came out with 8.366
but my online homework says that answer is incorrect I don't know why isn't it basically the same question but with a different number
 
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lilaznjewel said:

Homework Statement


Given: A flat dance floor of dimensions ℓx =
19 m by ℓy = 23 m and has a mass of M =
1600 kg. Use the bottom left corner of the
dance floor as the origin. Three dance couples,
each of mass m = 150 kg start in the top left,
top right, and bottom left corners.
What is the initial y coordinate of the cen-
ter of gravity of the dance floor and three
couples?
Answer in units of m.

The couple in the bottom left corner moves
ℓx = 10 m to the right. What is the new x
coordinate of the center of gravity?


Homework Equations


xcm =
m1x1 + m2x2/
m1 + m2


The Attempt at a Solution



for the first part I did 1600(y-11.5)+150(y-23)+150(y-0)+150(y-23)=0
and solved for y and I got 12.34
and I got it right

my problem is I did the exact same thing for the next part just you know used the X coordinates and moved (0,0) to (10,0)
1600(x-8)why are you using 1600(x-8)? Shouldn't it be 1600(x-9.5)?[/color] +150(x-0)+150(x-10)+150(x-19)=0
I came out with 8.366
but my online homework says that answer is incorrect I don't know why isn't it basically the same question but with a different number
see correction above[/color]. Your method is OK, although it is a bit cumbersome.
 
omg I am so stupid. Thank you for pointing out my mistake!
 

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