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Center of gravity (x and y coordinates) of mechinist's square

  1. Mar 11, 2012 #1
    1. The problem statement, all variables and given/known data
    The machinist's square shown in the figure consists of a thin, rectangular blade connected to a rectangular handle. Determine the x and y coordinates of the center of gravity. Let the lower corner be x=0, y=0.
    problem53.png

    2. Relevant equations
    x_cg = (m_1 * x_1)+(m_2 * x_2)...../(m_1+m_2+.......)
    y_cg = ............................... (same thing, but y)


    3. The attempt at a solutionp

    I have gotten an answer, but it is not matching up with the back of the book. Here are the numbers I used to get my answer:

    x_1 = 4cm
    x_2 = 12cm
    y_1 = 11cm
    y_2 = 3.0cm

    for x_cg I have: [(4cm*40g)+(12cm*80g)] / (40g+80g)= 9.3cm
    for y_cg I have: [(11cm*40g)+(3.0cm*80g)] / (40g+80g)= 5.67cm

    What did I do wrong? Thank you for any help! :smile:
     
  2. jcsd
  3. Mar 11, 2012 #2

    OldEngr63

    User Avatar
    Gold Member

    You did not think about where the cm for the components were. You simply took the given dimensions and started plugging in numbers. Go back and think about these quantities carefully before you start calculating. Then you will get the right answer.
     
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