Center of gravity (x and y coordinates) of mechinist's square

[chinnie15]

Homework Statement

The machinist's square shown in the figure consists of a thin, rectangular blade connected to a rectangular handle. Determine the x and y coordinates of the center of gravity. Let the lower corner be x=0, y=0.

Homework Equations

x_cg = (m_1 * x_1)+(m_2 * x_2).../(m_1+m_2+...)
y_cg = ...... (same thing, but y)

The Attempt at a Solution

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I have gotten an answer, but it is not matching up with the back of the book. Here are the numbers I used to get my answer:

x_1 = 4cm
x_2 = 12cm
y_1 = 11cm
y_2 = 3.0cm

for x_cg I have: [(4cm*40g)+(12cm*80g)] / (40g+80g)= 9.3cm
for y_cg I have: [(11cm*40g)+(3.0cm*80g)] / (40g+80g)= 5.67cm

What did I do wrong? Thank you for any help!

 

[OldEngr63]

You did not think about where the cm for the components were. You simply took the given dimensions and started plugging in numbers. Go back and think about these quantities carefully before you start calculating. Then you will get the right answer.