How Does Dolphin Movement Affect Sound Frequency Perception?

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SUMMARY

The forum discussion centers on the calculation of sound frequency perception in dolphins using the Doppler effect. A marine biologist measures the frequency of clicks emitted by a dolphin swimming away at 9.8 m/s in seawater, where the speed of sound is 1523 m/s. The observed frequency is calculated to be 2230 Hz, while the source frequency is determined to be 2244 Hz, resulting in a difference of -14 Hz. The discrepancy arises from the interpretation of the difference in frequencies and the potential need for more significant figures in the answer.

PREREQUISITES
  • Understanding of the Doppler effect in sound waves
  • Familiarity with basic physics equations related to frequency and speed
  • Knowledge of marine biology concepts related to dolphin communication
  • Proficiency in using significant figures in scientific calculations
NEXT STEPS
  • Study the Doppler effect and its applications in marine biology
  • Learn about sound propagation in different mediums, focusing on seawater
  • Explore the significance of significant figures in scientific measurements
  • Investigate echolocation mechanisms in dolphins and other marine mammals
USEFUL FOR

This discussion is beneficial for marine biologists, physics students, and anyone interested in the acoustic behavior of marine animals, particularly in understanding how movement affects sound frequency perception.

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Homework Statement


Dolphins emit clicks of sound for communication and echolocation. A marine biologist is monitoring a dolphin swimming in seawater where the speed of sound is 1523 m/s. When the dolphin is swimming directly away at 9.8 m/s, the marine biologist measures the number of clicks occurring per second to be at a frequency of 2230 Hz. What is the difference (in Hz) between this frequency and the number of clicks per second actually emitted by the dolphin?


Homework Equations


Fo = Fs(1/(1+v/Vs))

Fo = Frequency heard by observer
Fs = Frequency of source
v = speed of dolphn
Vs = speed of sound in water


The Attempt at a Solution


2230 = Fs(1/1+(9.8/1523))

2230 = (0.9936)Fs

Fs = 2244

Difference between Fs and Fo = 14 Hz. However the answer is showing as incorrect when I input it online. Any idea what I am doing wrong?
 
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Hi bfitzp

I actually used a sort of "common sense" approach to solving the problem (without resorting to that Doppler shift equation) and I got the same answer as you did. So I'm not sure what's wrong. The only thing I can think of is that the problem asks you for the difference between the observed and source frequencies, which would actually be -14 Hz (since the observed frequency < source frequency).

Either that, or your computer wants more sig. figs.?
 

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