A kid is riding a bike and is ringing bell of 3000 Hz. You are standing still on the sidewalk.When the bicycle moves toward you, you hear a shift in the frequency of the bell. In addition, when the bicycle moves away from you, you hear a different shift in the frequency of the bell. If there is a 30 Hz change in the frequencies that you hear for the bell as the bicycle approaches you and then moves away from you, what is the speed (in m/s) of the bicycle? (Write your answer to the nearest 0.01 m/s.) 1. The problem statement, all variables and given/known data Frequency(source)(fs) = 3000 Hz speed(observer)(vo) = 0 m/s Frequency(towards)(ft)= 3030 Hz (NOT SURE) Frequency(away)(fa) = 2970 Hz (NOT SURE) speed of sound(v) = 343 m/s 2. Relevant equations fo = ((v+vo)/(v-vs)) * fs Bike is moving TOWARDS me fo = ((v-vo)/(v+vs)) * fs Bike is moving AWAY from me 3. The attempt at a solution Towards ------------ 3030Hz/3000Hz = (343 m/s) / (343 m/s - vs) (1.01)(343 m/s - vs) = 343 m/s 345.20 m/s - 1.01 vs = 343 m/s vs = 2.18 m/s I do the same thing using the AWAY equation, and i get the same answer. However, that answer is incorrect. I do not know what I am doing wrong.