How Does Doubling Mass and Reducing Distance Affect Gravitational Force?

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SUMMARY

The gravitational force experienced by a spaceship is calculated using the formula F = G(M_e m_1)/r². When the mass is doubled and the distance from the Earth's center is reduced to one-fourth, the resulting force of gravity increases to 28,800N. This conclusion is reached by applying the principles of proportionality inherent in the gravitational force equation. The calculations confirm that the derived answer is accurate and aligns with the established gravitational principles.

PREREQUISITES
  • Understanding of Newton's Law of Universal Gravitation
  • Familiarity with gravitational constant (G)
  • Basic algebra for manipulating equations
  • Knowledge of mass and distance relationships in physics
NEXT STEPS
  • Study the implications of changing mass in gravitational equations
  • Explore the effects of varying distance on gravitational force
  • Learn about the gravitational constant (G) and its significance
  • Investigate real-world applications of gravitational force calculations
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Students studying physics, educators teaching gravitational concepts, and anyone interested in the mathematical relationships governing gravitational forces.

linuxux
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Homework Statement



Force of gravity on a spaceship is 900N. What is the force when mass is double and distance from Earth center is 1/4 as far?


The Attempt at a Solution



the answer i got was 28800N, but i just applied proportionalities apparent from in the equation [tex]F=G\frac{M_{e}m_1}{r^2}[/tex] . Is it the right answer?
 
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Yeah. Thats right.
 

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