How Does Doubling the Force Affect the Speed of an Arrow?

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An arrow, starting from rest, leaves the bow with a speed of 25.0m/s. If the average force exerted on the arrow by the bow were doubled, all else remaining the same, with what speed would the arrow leave the bow?


Any point in the right direction would help :) but I have been trying to solve this problem for the past half hour.

If anyone can work me through the problem that would be extra great.. i wish i can return the favor. TY


Homework Equations



Laws of Kinematics and Neutons Laws of Force(1 and 2)



The Attempt at a Solution



Im stuck

 
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when the force is doubled, so is the acceleration (since F=m*a) ..
it is said that all else remaining the same (x is the same for both cases) ..

and you have for your first case:
vo = 0 m/s , vf = 25 m/s , a = a m/s^2 , x = x m

for the second case:
vo = 0 m/s , vf = ? m/s , a = 2a m/s^2 , x = x m


hint: there is one of the kinematic equations you can use to find your answer .. :)
 
Try think about how the force and distance involved in accelerating the arrow is related to the work imposed on the arrow, and then how this work is related to kinetic energy and speed of the arrow.