1. The problem statement, all variables and given/known data An arrow, starting from rest, leaves the bow with a speed of 25.0m/s. If the average force exerted on the arrow by the bow were doubled, all else remaining the same, with what speed would the arrow leave the bow? 2. Relevant equations F = ma 3. The attempt at a solution For a force, F, the launch velocity of the arrow was 25.0m/s. Acceleration is F/m and multiplying F/m by a time t gives velocity at time t. So I re-wrote the first scenario as 25.0m/s = t/m * F. In the second scenario the force is doubled (2F), so I re-wrote the velocity as Xm/s = t/m * 2F. Since t and m remain the same for both scenarios, is the velocity of the 2nd scenario simply that of the 1st scenario's but doubled (50m/s)?