How Does Electron Kinetic Energy Compare to Hydrogen's Ground State?

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SUMMARY

The kinetic energy of an electron with a de Broglie wavelength equal to the diameter of a hydrogen atom in its ground state is calculated to be 1.17e-20 J or 0.0732 eV. This calculation uses the formula λ = h/mv, with the diameter defined as 2 times the Bohr radius (1.06e-10 m). A critical error was identified in the initial attempt, where the mass of the electron was incorrectly substituted with the mass of the proton, leading to significant discrepancies in the results. Correcting this error is essential for accurate energy comparison with the ground-state energy of hydrogen.

PREREQUISITES
  • Understanding of de Broglie wavelength and its application in quantum mechanics
  • Familiarity with the Bohr model of the hydrogen atom
  • Knowledge of kinetic energy calculations in physics
  • Proficiency in using fundamental constants such as Planck's constant and electron mass
NEXT STEPS
  • Review the derivation of the de Broglie wavelength formula
  • Study the Bohr model and its implications for atomic structure
  • Explore the relationship between kinetic energy and potential energy in quantum systems
  • Investigate common errors in mass substitution in physics calculations
USEFUL FOR

Students in physics, particularly those studying quantum mechanics and atomic theory, as well as educators looking to clarify concepts related to electron behavior and energy calculations.

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Homework Statement



An electron has a de Broglie wavelength equal to the diameter of a hydrogen atom in its ground state.
What is the kinetic energy of the electron?

How does this energy compare with the ground-state energy of the hydrogen atom?

Homework Equations



λ = h /mv
diameter = 2 x bohr radius = 1.06e-10 m

The Attempt at a Solution



1.06e-10 = 6.63e-34/1.67e-27v
v = 3.75e3 m/s
.5(1.67e-27)(3.75e3)^2 = 1.17e-20 J = .0732 eV
Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully.
 
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Woopy said:

Homework Statement



An electron has a de Broglie wavelength equal to the diameter of a hydrogen atom in its ground state.
What is the kinetic energy of the electron?

How does this energy compare with the ground-state energy of the hydrogen atom?

Homework Equations



λ = h /mv
diameter = 2 x bohr radius = 1.06e-10 m

The Attempt at a Solution



1.06e-10 = 6.63e-34/1.67e-27v
v = 3.75e3 m/s
.5(1.67e-27)(3.75e3)^2 = 1.17e-20 J = .0732 eV
Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully.


Well, your electron mass doesn't look right at all. I suspect that you used the value for the proton mass rather than the electron mass. They're different by a factor of more than 1000.
 
hah that was it. Thanks
 

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