How Does Electron Kinetic Energy Compare to Hydrogen's Ground State?

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Homework Statement



An electron has a de Broglie wavelength equal to the diameter of a hydrogen atom in its ground state.
What is the kinetic energy of the electron?

How does this energy compare with the ground-state energy of the hydrogen atom?

Homework Equations



λ = h /mv
diameter = 2 x bohr radius = 1.06e-10 m

The Attempt at a Solution



1.06e-10 = 6.63e-34/1.67e-27v
v = 3.75e3 m/s
.5(1.67e-27)(3.75e3)^2 = 1.17e-20 J = .0732 eV
Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully.
 
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Woopy said:

Homework Statement



An electron has a de Broglie wavelength equal to the diameter of a hydrogen atom in its ground state.
What is the kinetic energy of the electron?

How does this energy compare with the ground-state energy of the hydrogen atom?

Homework Equations



λ = h /mv
diameter = 2 x bohr radius = 1.06e-10 m

The Attempt at a Solution



1.06e-10 = 6.63e-34/1.67e-27v
v = 3.75e3 m/s
.5(1.67e-27)(3.75e3)^2 = 1.17e-20 J = .0732 eV
Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully.


Well, your electron mass doesn't look right at all. I suspect that you used the value for the proton mass rather than the electron mass. They're different by a factor of more than 1000.
 
hah that was it. Thanks
 

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