How Does Enthalpy Relate to Heat Capacity at Constant Composition?

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Homework Statement


Demonstrate that [itex]C_{Y,N}=\left ( \frac{ \partial H}{\partial T } \right ) _{Y,N}[/itex] where H is the enthalpy and Y is an intensive variable.


Homework Equations


(1) [itex]C_{Y,N}=\frac{T}{N} \left ( \frac{ \partial S}{\partial T } \right ) _{Y,N}[/itex]
(2) [itex]T= \left ( \frac{ \partial U}{\partial S } \right ) _{X,N}[/itex] where X is an extensive variable.

The Attempt at a Solution


Using (1) and (2) I reach that [itex]C_{Y,N}=T \left ( \frac{ \partial S}{\partial T } \right ) _{Y,N}+ P \left ( \frac{ \partial V}{\partial T } \right ) _{Y,N}[/itex]. I don't know how to proceed further, I'm really stuck here.
 
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I like Serena said:
Which intensive variables are we talking about?
What do you get if you pick the first one that springs to mind?
Usually the pressure, but it is not specified.
[itex]C_{P,N}=\frac{T}{N} \left ( \frac{ \partial S}{\partial T } \right ) _{P,N}[/itex].
Where [itex]\left ( \frac{ \partial S}{\partial T } \right ) _{P,N}=\left ( \frac{ \partial U}{\partial T } \right ) _{P,N}\left ( \frac{ \partial S}{\partial U } \right ) _{P,N}=\frac{1}{T} \left ( \frac{ \partial U}{\partial T } \right ) _{P,N}[/itex].
Thus [itex]C_{P,N}= \frac{1}{N} \left ( \frac{\partial U }{\partial T } \right ) _{P,N }[/itex].
Now I use the relation [itex]U=H-PV[/itex] to get [itex]\left ( \frac{ \partial U}{\partial T } \right ) _{P,N}=\left ( \frac{ \partial H}{\partial T } \right ) _{P,N} - \left [ \underbrace { \left ( \frac{ \partial P}{\partial T } \right ) _{P,N} V }_{=0} + P \left ( \frac{ \partial V}{\partial T } \right ) _{P,N} \right ][/itex].
Therefore I'm left with [itex]C_{P,N}=\frac{1}{N} \left [ \left ( \frac{ \partial H}{\partial T } \right ) _{P,N} - P \left ( \frac{ \partial V}{\partial T } \right ) _{P,N} \right ][/itex].
 
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Hmm, let's start with H=U+PV, or rather dH=TdS+VdP.

When I take the partial derivative with respect to T, and with P,N constant, I almost get what you're looking for (typo?).
 
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I like Serena said:
Hmm, let's start with H=U+PV, or rather dH=TdS-VdP.

When I take the partial derivative with respect to T, and with P,N constant, I almost get what you're looking for (typo?).
Hmm I don't think there's a typo.
Anyway you took the partial derivative of "dH"? I'm having some troubles to figure this out :)