How Does Force Affect a Duck's Displacement in Water?

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Homework Help Overview

The problem involves analyzing the motion of a duck in water, specifically how the forces acting on it affect its displacement over a given time. The subject area includes dynamics and kinematics, focusing on force, mass, and displacement calculations.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss breaking down the problem into x and y components to clarify the calculations. There is a focus on finding the components of the force and acceleration before determining the displacement. Questions arise regarding the values used for force, particularly the discrepancy between 20 N and the smaller values mentioned.

Discussion Status

The discussion is ongoing, with participants seeking clarity on the calculations and components involved. Some guidance has been offered on separating the components for better understanding, but there is no explicit consensus on the correct approach or values at this point.

Contextual Notes

There are potential typographical errors in the force values provided, which may affect the calculations. The original poster mentions rounding in their calculations, which could also influence the results.

afcwestwarrior
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Homework Statement

A duck has a mass of 2.5 kg. As the duck paddles, a force of the water exerts a force of 20.0 N in a direction of 52 degrees south of east. When these forces begin to act, the velocity of the duck is .11 m/s in a direction due east. Find the magnitude and direction ( relative to due east) of the displacement that the duck undergoes 3.0 s while the forces are acting.

time=3.0s
angle=52 degrees
F=.20 N
F=.10N
Mass of duck=2.5 kg



Homework Equations


Acos 52 degrees
A sin 52 degrees

x=Vox(t) + Ax (t)^2/ 2


The Attempt at a Solution



I figured out the x component, and I got .20cos 52=.123 N
Then I added .10 N + .123 =.223 N
Then I figured out the acceleration .233 N/ 2.5 kg= .089 m/s^2
(if your getting a different answer then me it's because I rounded off, but I'm still using the exact numbers on my calculator such as
.1231222951)

Then I used that kinematic equation x= .11 m/s (3.0 s) + (.089 m/s^2) (3.0s)^2/2 = .7305 m

In the back of my book the answer is .78 meters. What did I do wrong.
 
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Your solution is a bit hard to follow. Try solving for the x (east) and y (north) components separately. Find the components of the force, then the acceleration. Then solve for the displacement components, then the total displacement.
 
Components of the force
 
afcwestwarrior said:
Components of the force

The question mentions 20N. But you use 0.20N and 0.10N... I assume the 0.20 is a typo but where is the 0.10 coming from?
 

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