How Do the Forces Affect the Duck's Displacement in 3.0 Seconds?

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The discussion focuses on calculating the displacement of a duck with a mass of 2.5 kg under the influence of two forces: 0.10 N due east and 0.20 N at 52 degrees south of east. The participant successfully derived the x and y components of the forces, determining the y component to be 0.16 N and the total x component to be 0.22 N. The duck's initial velocity is 0.11 m/s, and the goal is to calculate the duck's displacement over a time period of 3.0 seconds while these forces are acting.

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the question is: A duck has a mass of 2.5 kg. As the duck paddles, a force of 0.10N acts on it in a direction due east. In addition, the current of the water exerts a force of 0.20N in a direction of 52 degrees south of east. When these forces begin to act, the celocity of the duck is 0.11m/s in a direction (relative to due east) of the displacement that the duck undergoes in 3.0s while the forces are acting.

I got the x and y components but I am stuck as to where to go from there??
 
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What's the actual question; could you quote it word for word, please?

You should also show some work before we can help you. What have you done thus far? How did you find the x and y components?
 
That was the actual question word for word.

I took the .20N due east and took it times the sin of 52 to give me the y component which gives me .16N
and to find the x component I took the .20N times the cos of 52 to give me one of the x-components and added it to the .10N already stated that was due east and it gave me
.22N
 

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