1. The problem statement, all variables and given/known data A duck has a mass of 3.0 kg. As the duck paddles, a force of 0.06 N acts on it in a direction due east. In addition, the current of the water exerts a force of 0.13 N in a direction of 60° south of east. When these forces begin to act, the velocity of the duck is 0.12 m/s in a direction due east. Find the magnitude and direction (relative to due east) of the displacement that the duck undergoes in 2.0 s while the forces are acting. 2. Relevant equations ƩF = m*a D = VoT + (1/2)aT^2 3. The attempt at a solution Fx = 0.06 + cos(60)*.13 = .125 m/s Fy = sin(60)*.13 = .113 m/s sqrt(.125^2 + .113^2) = .1685N .1685/3.0 = 0.0561 m/s^2 D = (0.12)(2) + (1/2)(.0561)(2)^2 = .3522 This is where I am confused, as I think I thought I was doing everything correct up until this point. When I enter this into the answer sheet it says it is wrong. I mistakenly used .13 for Fy instead of .113 and it gave me .326 m which is the correct answer. Also I know to find the direction you use arctan(Fy/Fx) but I can't find it... Any help is greatly appreciated. Thank you.